-29m-28-6m^2=0

Solution for -29m-28-6m^2=0 equation:

-29m-28-6m^2=0

a = -6; b = -29; c = -28;
Δ = b2-4ac
Δ = -292-4·(-6)·(-28)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-13}{2*-6}=\frac{16}{-12}
=-1+1/3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+13}{2*-6}=\frac{42}{-12}
=-3+1/2
$